Q.1
Algorithm:
Greedy_Act_sel(S,F)
{
Nßlength[S]
|
|
Aß{a}
Iß1
for(mß2 to n)
{
If(Sm>Fi)then
AßA U {am}
Ißm
}
return A;
}
Example:-consider following set of activities
the set of activities sorted in ascending order.
|
i
|
1
|
2
|
3
|
4
|
5
|
6
|
7
|
8
|
9
|
10
|
11
|
|
si
|
1
|
3
|
0
|
5
|
3
|
5
|
6
|
8
|
8
|
2
|
12
|
|
fi
|
4
|
5
|
6
|
7
|
8
|
9
|
10
|
11
|
12
|
13
|
14
|
Step
1: Sort fi into non
decreasing order. After sorting, f1 £
f2 £ f3 £ … £ fn.
Step
2: Add the next activity i to the
solution set if i is compatible with each in the solution set.
Step
3: Stop if all activities are examined.
Otherwise, go to step 2.
From the above set first of all
we will select i1.the finish time of i1 is 4
I1-> si=1 Fi=4
So add in the list {i1} then select the next activity whose
starting time is greater than i1
I4-> si=5
Fi=7
So at that way finally we get solution set is {1, 4, 8, 11}
Time complexity: O(nlogn)
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